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Recursive function to find the factorial of a positive number

Recursive function to find the factorial of a positive number:

        unsigned long int rfact(unsigned long int num)
         if (num==0)
          return 1;
           return n*rfact(n-1);

In the above function (num==0), is the base condition. When this condition is true then the recursive call is terminated. In the recursive call you can observe that every time the actual parameter value is changed. It is necessary to reach to the base condition. Suppose that the recursive function is called with a parameter 4. Then the function will return the value of the expression 4*rfact(3); it means the function rfact() is called i.e. recursion. So, the function will return the value only after getting the value of rfact() is again called with parameter 2. So, till the base condition is satisfied the same function is called again by again by changing the parameter. When the parameter is 0 for the rfact(), the call terminates by returning 1. Then one by one all the function calls will be terminated in the reverse order of their calls. This is called as backtracking. So the call rfact(0) returns 1, rfact(1) also returns 1, rfact(2) returns 2, rfact(3) returns 6, rfact(4) returns 24. 24 is the final value returned by the first function call. So the factorial value of 4 is 24.

Recursive function to find ‘gcd’ of two positive numbers:
int rgcd(int a, intb)
    if (a%b=0)
       return b;
      rgcd(b, a%b);


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Memory representation of Linked List

             In memory the linked list is stored in scattered cells (locations).The memory for each node is allocated dynamically means as and when required. So the Linked List can increase as per the user wish and the size is not fixed, it can vary.

               Suppose first node of linked list is allocated with an address 1008. Its graphical representation looks like the figure shown below:

      Suppose next node is allocated at an address 506, so the list becomes,

  Suppose next node is allocated with an address with an address 10,s the list become,

The other way to represent the linked list is as shown below:

 In the above representation the data stored in the linked list is “INDIA”, the information part of each node contains one character. The external pointer root points to first node’s address 1005. The link part of the node containing information I contains 1007, the address of next node. The last node …