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How to deploy windows phone 8.1 application to device

If you want to run your windows phone 8.1 application to your physical device or you can say phone that you can follow these instruction which is mentioned below:
1. Search windows phone developer registration 8.1 from your window start screen.


windows phone 8.1 registration

2. Register your windows phone now.

windows phone 8.1 registration

3. After successfully registration, set platform of windows phone by build menu in visual studio like:

Configuration manager of build menu
4. Select Platform as "ARM" from Dropdown option.

windows phone device
 5. Now, connect your phone with your computer from USB cable.
6. Run your application.

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difference between structure and union in C Language

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Difference between Linear search and Binary Search in c language

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Binary Search Linear Search Works only on sorted items. such as  1,2,3,4,5,6  etc
Works on sorted as well as unsorted items. 12,4,5,3,2,1 etc Very efficient if the items are sorted Very efficient if the items are less and present in the beginning of the list. such as Suppose your list items are : 12,3,4,5,1 and you want to search 12 number then you get beginning in the list. Works well with arrays and not on linked lists. Works with arrays and linked lists.
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Memory representation of Linked List

             In memory the linked list is stored in scattered cells (locations).The memory for each node is allocated dynamically means as and when required. So the Linked List can increase as per the user wish and the size is not fixed, it can vary.

               Suppose first node of linked list is allocated with an address 1008. Its graphical representation looks like the figure shown below:


      Suppose next node is allocated at an address 506, so the list becomes,



  Suppose next node is allocated with an address with an address 10,s the list become,


The other way to represent the linked list is as shown below:




 In the above representation the data stored in the linked list is “INDIA”, the information part of each node contains one character. The external pointer root points to first node’s address 1005. The link part of the node containing information I contains 1007, the address of next node. The last node …