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Creating Scalar functions in SQL

In earlier article we have discussed about user defined functions that have the limited scope in sql programming in compare to stored procedures. User defined function have two types i.e. scalar function and table-valued function. In this article we will discuss about scalar functions.

Scalar function accept a single parameter and return a single data value of the type specified in the RETURNS clause. A scalar function can return any data type except text, ntext, image, cursor, and timestamp. Some scalar functions, such and current_timestamp, do not require any arguments.

A function contains a series of T-SQL statements defined in a BEGIN…END block of the function body that returns a single value.

Consider an example of a scalar function that calculates the monthly salary of the employees accepting the pay rate as an input and returning a single value after multiplying the value with the number of hours and number of days:

CREATE FUNCTION HumanResources.MonthlySal (@PayRate float)
RETURN float
RETURN (@PayRate * 8 * 30)

You can execute this function by using the following statements:

DECLARE @PayRate float
SET @PayRate = HumanResources.MonthlySal (12.25)
PRINT @PayRate

In the preceding code, @PayRate is a variable that will store a value returned by the MonthlySal function.


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Binary Search Linear Search Works only on sorted items. such as  1,2,3,4,5,6  etc
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Memory representation of Linked List

             In memory the linked list is stored in scattered cells (locations).The memory for each node is allocated dynamically means as and when required. So the Linked List can increase as per the user wish and the size is not fixed, it can vary.

               Suppose first node of linked list is allocated with an address 1008. Its graphical representation looks like the figure shown below:

      Suppose next node is allocated at an address 506, so the list becomes,

  Suppose next node is allocated with an address with an address 10,s the list become,

The other way to represent the linked list is as shown below:

 In the above representation the data stored in the linked list is “INDIA”, the information part of each node contains one character. The external pointer root points to first node’s address 1005. The link part of the node containing information I contains 1007, the address of next node. The last node …