Uploading a file is need some Html code with setting the encoding type to multipart/form-data and the method of form is post. After setting this type, programmer have to use file upload control having the property name and id. Here is the code written in the view page:
@using (Html.BeginForm(null, null, FormMethod.Post, new { enctype = "multipart/form-data" }))
{
<div>
<input type="file" name="file" id="file"/>
</div>
<input type="submit" value="Upload" />
}
This code will place a file upload control to browse a single file of any type of extension and a submit button which will help to post this file to action. Now our action method must have a specific parameter written below in the code:
public ActionResult GetValues(HttpPostedFileBase file)
{
var fileName = System.IO.Path.GetFileName(file.FileName);
var path = System.IO.Path.Combine(Server.MapPath("Path/"), fileName);
file.SaveAs(path);
…………
………..
In this action method programmer can easily get this file and can save this file as done in above code. This code is for uploading/accessing single file, what if programmer want to upload multiple files.
To upload multiple files in view page, just change the file upload control as written below:
<input type="file" name="files" id="files" multiple/>
In the action method of controller change the parameter as written below:
public ActionResult GetValues(IEnumerable<HttpPostedFileBase> files)
{
foreach (var file in files)
{
}
……..
……..
All the files can easily accessed and using the foreach loop, programmer can perform individual action with these files. If programmer want to limit the no. of files to be uploaded by the user, no. of file upload control can be used in the view page and action code will remain same as is.
What if two files are uploaded with the same name, the previous file will be overwritten by the new one. To overcome with these issues we can rename the file when we are saving them like unique identifier or may be other unique name. Programmer can also perform some validation discussed earlier.
@using (Html.BeginForm(null, null, FormMethod.Post, new { enctype = "multipart/form-data" }))
{
<div>
<input type="file" name="file" id="file"/>
</div>
<input type="submit" value="Upload" />
}
This code will place a file upload control to browse a single file of any type of extension and a submit button which will help to post this file to action. Now our action method must have a specific parameter written below in the code:
public ActionResult GetValues(HttpPostedFileBase file)
{
var fileName = System.IO.Path.GetFileName(file.FileName);
var path = System.IO.Path.Combine(Server.MapPath("Path/"), fileName);
file.SaveAs(path);
…………
………..
In this action method programmer can easily get this file and can save this file as done in above code. This code is for uploading/accessing single file, what if programmer want to upload multiple files.
To upload multiple files in view page, just change the file upload control as written below:
<input type="file" name="files" id="files" multiple/>
In the action method of controller change the parameter as written below:
public ActionResult GetValues(IEnumerable<HttpPostedFileBase> files)
{
foreach (var file in files)
{
}
……..
……..
All the files can easily accessed and using the foreach loop, programmer can perform individual action with these files. If programmer want to limit the no. of files to be uploaded by the user, no. of file upload control can be used in the view page and action code will remain same as is.
What if two files are uploaded with the same name, the previous file will be overwritten by the new one. To overcome with these issues we can rename the file when we are saving them like unique identifier or may be other unique name. Programmer can also perform some validation discussed earlier.