Skip to main content

How to Retrieve XML Data Using XQuery

In addition to FOR XML, SQL Server allows programmer to extract data stored in variables or columns with the XML data type by using XQuery. XQuery is a language that uses a set of statements and functions provided by the XML data type to extract data. As compared to the FOR XML clause of the SELECT statement, the XQuery statements allow you to extract specific parts of the XML data.

Each XQuery statement consists of two parts, prolog and body. In the prolog section, you declare the namespaces. In addition, schemas can be imported in the prolog. The body parts specifies the XML nodes to be retrieved. The XQuery language includes the following statements:

  • For: Used to iterate through a set of nodes at the same level as in an XML document.
  • Let: Used to declare variables and assign values.
  • Order by: Used to specify a sequence.
  • Where: Used to specify criteria for the data to be extracted.
  • Return: Used to specify the XML returned from a statement.

The XQuery statements also use the following functions provided by the XML data type:

Query: Used to extract XML from an XML data type. The XML to be retrieved is bicycle is manufactured at AdventureWorks, it passes through a series of work centre locations. Each work centre location produces a different cycle component. Therefore, the number of production steps varies between different work centres.

To analyse the production process, the management of AdventureWorks needs to retrieve a list of the location IDs of all the work centers, which have more than four steps. You need to generate the list displaying the location ids in the ascending order of the steps included in the work centres.

To perform this task, the database developer can create the following query:

SELECT Instructons.query
(‘ declare namespace
ns=http://schemas.microsoft.com/sqlserver/2004/07/adventure-works/ProductModelManuInstructions:
for $work in /ns:root/ns:Location
where count(#work/ns:step) > 4
order by count ($work/ns:step)
return
count($work/ns:step)’) AS Result
FROM Production.ProductModel
WHERE Instructions IS NOT NULL

Value: Used to return a single value from an XML document. To extract a single value, you need to specify an XQuery expression that identifies a single node and a data type of the value to be retrieved.

For example, the management of AventureWorks, Ins. Wants a list containing the product model id, product name, machine hours, and labour hours. However, not all product have production instructions. As a database developer, you have stored this data in the XML format in the ProductModel table. You can create the following query to display the results:

SELECT ProductModelID, Name, Instructions.value (‘declare namespace ns=”http//schemas.microsoft.com/sqlserver/2004/07/adventure-works/ProductManuInstructions”;
(/ns:root/ns:Location/@LaborHours) [1]’, ‘float’)AS
LaborHours,
Instructions.value(declare namespace
Ns=”http://schemas.microsoft.com/sqlserver/2004/07/adventure-works/ProductModelManuInstructions”;
(/ns:root/ns:Location/@MachineHours) [1]’, ‘float’) AS MachineHours
FROM Production.ProductModel
WHERE Instructions IS NOT NULL

Exist: Used to check the existence of a node in an XML data. The function returns I if the specified node exists else it returns 0. For example, the management of AdventureWorks, wants the details of all the customers in the city ‘NJ’. The details of all the customers are stored in an XML format in the CustDetails table. You can use the following query to display the results:

SELECT Cust_ID, Cust_Details.exist
(‘Customer[@City=’NJ”]’) AS ‘True’ FROM CustDetails

Retrieve XML data from DataSet

Comments

Popular posts from this blog

difference between structure and union in C Language

In c language article we will see the difference between union and structure. Both are the user define datatype in c language. See the table which is mentioned below: ASP.NET Video Tutorial Series Structure Union1.The keywordstruct is used to define a structure 1. The keyword union is used to define a union. 2. When a variable is associated with a structure, the compiler allocates the memory for each member. The size of structure is greater than or equal to the sum ofsizes of its members. The smaller members may end with unused slack bytes. 2. When a variable is associated with a union, thecompiler allocates thememory by considering the size of the largest memory. So, size of union is equal to the size of largest member. 3. Each member within a structure is assigned unique storage area of location. 3. Memory allocated is shared by individual members of union. 4. The address of each member will be in ascending order This indicates that memory for each member will start at different offset v…

Difference between Linear search and Binary Search in c language

SQL Video Channel : Download all SQL Video



Binary Search Linear Search Works only on sorted items. such as  1,2,3,4,5,6  etc
Works on sorted as well as unsorted items. 12,4,5,3,2,1 etc Very efficient if the items are sorted Very efficient if the items are less and present in the beginning of the list. such as Suppose your list items are : 12,3,4,5,1 and you want to search 12 number then you get beginning in the list. Works well with arrays and not on linked lists. Works with arrays and linked lists.
Number of comparisons are less More number of comparisons are required if the items are present in the later part of the array or its elements are more.

Memory representation of Linked List Data Structures in C Language

Memory representation of Linked List

             In memory the linked list is stored in scattered cells (locations).The memory for each node is allocated dynamically means as and when required. So the Linked List can increase as per the user wish and the size is not fixed, it can vary.

               Suppose first node of linked list is allocated with an address 1008. Its graphical representation looks like the figure shown below:


      Suppose next node is allocated at an address 506, so the list becomes,



  Suppose next node is allocated with an address with an address 10,s the list become,


The other way to represent the linked list is as shown below:




 In the above representation the data stored in the linked list is “INDIA”, the information part of each node contains one character. The external pointer root points to first node’s address 1005. The link part of the node containing information I contains 1007, the address of next node. The last node …