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How to Create a List of Item, with Multiple Fields: C#

If read more about DataTable, then follow How to Use DataTable in C#.

DataTable is the tabular form of data we are storing. Now to create a list, we have to create a list that can contains our desired set of data. List resides in System.Collection.Generic namespace of visual studio. Let suppose, we have a student class with some common properties like name, age, city, and date of birth.

To create a list, just create a list object type of student as in following line of c# code:
public class Student
{
public string Name { get; set; }
public int Age { get; set; }
public string City { get; set; }
public DateTime Dob { get; set; }
}

And the list object will create by the following line:

List<Student> stuList = new List<Student>();

This list can be used further like to insert new record of student, to bind this list with datagridview, to store temporary data from the database and many more. A list have many in-built functions, we have to just analyse them and use them.

This list is empty by default and can contains student type of data only. To insert some data in this list, we have to create a new object of student and then call the add() method of list. The add() method requires a parameter of student type. The syntax of method to add a new student is:
stuList.Add(new Student()
{
Name = "Jacob",
Age = 29,
City = "London",
Dob = new DateTime(1984, 5, 26)
});

This will add a single record of student with above details. We can add as many record as per our requirement.

In the next post we will use some in-built functions which requires Basics of LINQ language.

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Memory representation of Linked List

             In memory the linked list is stored in scattered cells (locations).The memory for each node is allocated dynamically means as and when required. So the Linked List can increase as per the user wish and the size is not fixed, it can vary.

               Suppose first node of linked list is allocated with an address 1008. Its graphical representation looks like the figure shown below:


      Suppose next node is allocated at an address 506, so the list becomes,



  Suppose next node is allocated with an address with an address 10,s the list become,


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 In the above representation the data stored in the linked list is “INDIA”, the information part of each node contains one character. The external pointer root points to first node’s address 1005. The link part of the node containing information I contains 1007, the address of next node. The last node …