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FileDialogBox control in Windows Forms

It is an abstract class, therefore we cannot instantiate it directly. We can use OpenFileDialog or SaveFileDialog to open a file or to save a file respectively. Just run the open or save dialog boxes is not sufficient to open or save a file, we have to use I/O streams to do these simple tasks.


To open an existing file and see the content of that file, OpenFileDialog box is used. It is same in all window application as shown in following image:

OpenFileDialog Box Control in windows forms

To open this dialog box just add an open file dialog control from toolbox and write openFileDialog1.ShowDialog(); in the click event of button.


To save a file after creating of modifying you have to save that file using SaveFileDialog box at the specified location. Following figure shows the preview of SaveFileDialog box.

SaveFileDialog Box Control in windows forms

To open this dialog box the same procedure will be followed up. Just add a SaveFileDialog and write saveFileDialog1.ShowDialog(); in the click event of button.

To open these type of dialog boxes we have to create an object of respective class and then call its ShowDialog() method:
OpenFileDialog openFileDialog = new OpenFileDialog();

FolderBrowserDialog Box Control


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Memory representation of Linked List

             In memory the linked list is stored in scattered cells (locations).The memory for each node is allocated dynamically means as and when required. So the Linked List can increase as per the user wish and the size is not fixed, it can vary.

               Suppose first node of linked list is allocated with an address 1008. Its graphical representation looks like the figure shown below:

      Suppose next node is allocated at an address 506, so the list becomes,

  Suppose next node is allocated with an address with an address 10,s the list become,

The other way to represent the linked list is as shown below:

 In the above representation the data stored in the linked list is “INDIA”, the information part of each node contains one character. The external pointer root points to first node’s address 1005. The link part of the node containing information I contains 1007, the address of next node. The last node …